5x^2-45x-16=0

Solution for 5x^2-45x-16=0 equation:

5x^2-45x-16=0

a = 5; b = -45; c = -16;
Δ = b2-4ac
Δ = -452-4·5·(-16)
Δ = 2345
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-45)-\sqrt{2345}}{2*5}=\frac{45-\sqrt{2345}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-45)+\sqrt{2345}}{2*5}=\frac{45+\sqrt{2345}}{10}
$